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Fórmulas Quimicas
1.Masa atomica
2.Composicion Porcentual
3.Formula Empirica
AlCl3
1.Masa Atomica
Al=1x27=27
Cl=3x35.45=106.35
133.35g/mol
2.Composicion Porcentual
Al=1x27=27
Cl=3x35.45=106.35
133.35g/mol
27gAl=100%AlCl3
133.35gAlCl3=20.24
106.35=100%AlCl3 133.35gAlCl3=79,75
79.75+20,24=99.99%
3.Formula Empirica
Al=20.23
Cl=79,76
100%
Al=20.23=20.23g
Cl=79,76=79,76g
Al=27g=1molAl
Cl=35,45g=1molCl
Al 20.23 x 1mol
27 = 0.74
Cl 79.76x1mol
35,45 =2.24 Al=0,74 Cl=2.24
0.74 =1 0.74=3
Alcl3
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